Thin Lenses

One usage of refraction, the bending of light rays, is lenses. There are two surface (air-to-medium and medium-to-air). If the surface are about spherical and also close together, one has actually what is dubbed a \"thin lens\". The results of the bending deserve to be simplified into an equation referred to as the slim lens equation

1/p + 1/q = 1/f.

In her report, you should tell me the definition of each of the quantities appearing in this equation. The variables are ranges from the lens to details points. So in addition to identifying these distances, you should answer the questions: What is \"the image\"? What is the \"focal point\"?

Part I.

Place a light resource and screen on opposite ends of an Optics bench. In between place among the thin lens significant +250 mm.


You are watching: 1/p + 1/q = 1/f

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readjust the place of the lens until the photo on the screen comes into focus.Note the distance from the source to lens (call it p) and the street from the display to the lens (call it q).The light resource has arrows drawn on it, one must be pointing up. Note whether the corresponding arrowhead in the picture is pointing increase or down.Measure the size of the source arrow, call it y0.Measure the size of the picture arrow, speak to it yi.Test the relationship
Next, without moving resource or screen, find an additional position of the lens for which the picture comes into focus. Measure p, q, yo and also yi.Decrease the distance between screen and resource (by a few centimeters) and repeat the over procedure. Find two sets of (p, q, yo, yi).Change the distance twice more finding two sets (p, q, yo, yi) for each distance. (Note if the display screen and source are too close friend cannot discover a position where the photo comes right into focus. In together a case you will need to increase distance between resource and screen.) her p and also q must obey the slim lens equation, check out above. The quantity f is the focal distance length. Resolve for f for your assorted sets of data.What street between resource and display screen is too close for one to carry the photo into focus? exactly how is it regarded f?


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