Just had a class there wherein the lecturer to be doing revision on digital configuration.

You are watching: Indium(iii) ion electron configuration

He stated that the digital configuration the $$ceIn^3+= 5s^2 3p^1$$

He didn"t incorporate the $ce4d^10$ orbital. He said it doesn"t matter and also if we write the full E.C the end it"s incorrect. It basically goes against everything we studied in 1st year basic inter-base.net. Likewise I believe he didn"t take into account the truth that $ceIn^3+$ has actually $46 , e^-$ no $49 , e^-$.

Should the electronic configuration no be $$ce 5s^0 4d^10 3p^0= ce 4d^10$$

Can someone melted some irradiate on even if it is he is right.

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edited Oct 31 "17 at 22:37

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asked Oct 31 "17 in ~ 12:22

Patrick MoloneyPatrick Moloney
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Yup, it"s $4d^10$. Post-transition ($p$-block) aspects rarely if ever before ionize or also covalently bond your $d$ subshell electrons. Return we use the bracketed main point designation just for noble gas cores, by the moment we acquire to team 12 or 13 the $d$ electron are likewise effectively part of the core.

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edited Oct 31 "17 at 19:15
answer Oct 31 "17 in ~ 12:58

Oscar LanziOscar Lanzi
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